What value resistor will discharge a 2.1 μF capacitor to 20 % of its initial charge in 2.4 ms ?
v = v₀e^(–t/RC)
0.2 = e^(–(2.4e-3)/R(2.1e-6))
solve for R
-1.609 = –(2.4e-3)/R(2.1e-6)
R = (2.4e-3)/(1.609)(2.1e-6)
R = 710 ohms
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