#### Answer

a). $v_{x}=32.9m/s$
$v_{y}=6.1m/s$
b). Magnitude of average velocity $=33.5m/s$
Angle = $\theta=10.5^{\circ}$ with respect to horizontal.
c). We cannot calculate the average speed, because we do not know its exact path, hence we do not know the distance covered.

#### Work Step by Step

a). $v_{x}=\frac{135}{4.1}=32.9m/s$
$v_{y}=\frac{25}{4.1}=6.1m/s$
b). Magnitude of average velocity $=\frac{\sqrt( 25^{2}+135^{2})}{4.1}=33.5m/s$
Angle = $\theta=tan^{-1} (\frac{25}{135})=10.5^{\circ}$
c). We cannot calculate the average speed, because we do not know its exact path, hence we do not know the distance covered.